postgresql如何找到表中重复数据的行并删除(spread 过去分词)万万没想到

随心笔谈12个月前发布 admin
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explain analyze delete from deltest a where a.ctid=any(array (select ctid from (select row_number() over (partition by id), ctid from deltest) t where t.row_number > 1));
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? ? Delete on deltest a ?(cost=250.74..270.84 rows=10 width=6) (actual time=98.363..98.363 rows=0 loops=1)
? ? InitPlan 1 (returns 0)?>SubqueryScanont(cost=204.95..250.73rows=509width=6)(actualtime=29.446..47.867rows=10000loops=1)Filter:(t.rownumber>1)RowsRemovedbyFilter:10000?>WindowAgg(cost=204.95..231.66rows=1526width=10)(actualtime=29.436..44.790rows=20000loops=1)?>Sort(cost=204.95..208.77rows=1526width=10)(actualtime=12.466..13.754rows=20000loops=1)SortKey:deltest.idSortMethod:quicksortMemory:1294kB?>SeqScanondeltest(cost=0.00..124.26rows=1526width=10)(actualtime=0.021..5.110rows=20000loops=1)?>TidScanondeltesta(cost=0.01..20.11rows=10width=6)(actualtime=82.983..88.751rows=10000loops=1)TIDCond:(ctid=ANY(0)?>SubqueryScanont(cost=204.95..250.73rows=509width=6)(actualtime=29.446..47.867rows=10000loops=1)Filter:(t.rownumber>1)RowsRemovedbyFilter:10000?>WindowAgg(cost=204.95..231.66rows=1526width=10)(actualtime=29.436..44.790rows=20000loops=1)?>Sort(cost=204.95..208.77rows=1526width=10)(actualtime=12.466..13.754rows=20000loops=1)SortKey:deltest.idSortMethod:quicksortMemory:1294kB?>SeqScanondeltest(cost=0.00..124.26rows=1526width=10)(actualtime=0.021..5.110rows=20000loops=1)?>TidScanondeltesta(cost=0.01..20.11rows=10width=6)(actualtime=82.983..88.751rows=10000loops=1)TIDCond:(ctid=ANY(0))
? ? Total runtime: 98.912 ms
select count(*) from deltest;
count
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10000

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